tag:blogger.com,1999:blog-4415570722844642835.post1981978797391533581..comments2024-03-05T22:36:18.660-08:00Comments on Christina's Chemistry Blog: Trimester 1 Exam Review Question #15crbowmanhttp://www.blogger.com/profile/04278646988556852649noreply@blogger.comBlogger4125tag:blogger.com,1999:blog-4415570722844642835.post-25296082741154147712010-11-14T15:25:05.078-08:002010-11-14T15:25:05.078-08:00Awesome explanation. One small critique - I wouldn...Awesome explanation. One small critique - I wouldn't say that the electrons outnumber the protons. The inner energy-levels act as "shields" for the outer-most energy-level because those outer electrons not only feel an attraction from the nucleus (+ charge) but a very large repulsion (- charge) from the inner shell electrons. the inner shells are literally in between the outer electrons and the nucleus blocking the attraction. <br /><br />When electrons are added to the same energy level you don't have this problem nearly as much which is why the attractive power seems to outweigh the repulsion from added electrons in the same energy-level when you go across the rows.jvanbuskirkhttps://www.blogger.com/profile/00864908872820721832noreply@blogger.comtag:blogger.com,1999:blog-4415570722844642835.post-80138872274988775052010-11-14T10:44:34.318-08:002010-11-14T10:44:34.318-08:00Great job Christina! your answer was very thorough...Great job Christina! your answer was very thorough and I feel like if I didn't understand this topic, it would have been very beneficial. I agree with Madison, it would have been a little helpful to show the increasing radius but it isn't crucial. Overall- very good explanation and answer!Emilyhttps://www.blogger.com/profile/12191072118929402281noreply@blogger.comtag:blogger.com,1999:blog-4415570722844642835.post-73937129705669171312010-11-13T19:23:46.855-08:002010-11-13T19:23:46.855-08:00Christina,
You did a really gread job on this blog...Christina,<br />You did a really gread job on this blog post! You gave a very complete and in-depth explainations of your answer. I also really liked the graphic of atomic radius was really helpful as well. Great job!Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4415570722844642835.post-66040476571578273322010-11-11T16:34:02.897-08:002010-11-11T16:34:02.897-08:00Christina,
You did a really good job on your answe...Christina,<br />You did a really good job on your answer and it was very complete. I think the only thing that may have helped more was a visual of the actual process of the increasing and decreasing of the radius, but you did really good!Madisonhttps://www.blogger.com/profile/15814701593069064268noreply@blogger.com